If the sum and product of the first three terms in an A.P. are 33 and 1155, respectively, then absolute value of its 11th term is

Suppose that three terms of an AP areSum of the terms isa−d+a+a+d=333a=33a=11Product of terms is 115511121−d2=1155121−d2=105d2=16d=±4If d=−4, First term is 15, common difference is - 4 , then the 11th term is T11=15+10−4=−25If d=4, first term is 7 and the 11th term is T11=7+40=47