If a variable takes the value 0, 1, 2, …... n with frequencies proportional to the binomial coefficients C0 n,C1 nC2 n,…,Cn n, then mean of distribution is
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a
n2
b
nn+12
c
nn-12
d
2n
answer is A.
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Detailed Solution
N= ∑i=1nfi=k nC0+nC1+......nCn=k⋅2n∑i=1nfixi= ∑i=1ni .k ci n =k⋅n2n−1 Mean= x¯= ∑i=1nfixiN=n⋅2n−12n=n2