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Q.

If a variable takes the value 0, 1, 2, …... n with frequencies proportional to the binomial coefficients C0   n,C1   nC2   n,…,Cn   n, then mean of distribution is

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a

n2

b

nn+12

c

nn-12

d

2n

answer is A.

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Detailed Solution

N= ∑i=1nfi=k nC0+nC1+......nCn=k⋅2n∑i=1nfixi= ∑i=1ni .k ci   n =k⋅n2n−1  Mean=    x¯= ∑i=1nfixiN=n⋅2n−12n=n2
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