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Questions  

If xi>0, 1in,  and x1+x2+x3+xn=π, then the greatest value of sinx1+sinx2+sinx3+...+sinxn=

a
n
b
π
c
nsinπn
d
0

detailed solution

Correct option is C

We have sinx1+sinx2+sinx3+….+sinxnn              ≤sinx1+x2+x3+….+xnn    since sin is concave in 0,π                ≤sinπn   ∵x1+x2+x3+….+xn=π⇒sinx1+sinx2+sinx3+….+sinxn≤nsinπn

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