Q.

If 0≤x≤2π and cosx≤sinx, then

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a

x∈0,π4

b

x∈π4,2π

c

π4,3π4

d

0,π

answer is C.

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Detailed Solution

We have cosx≤sinx⇒sinx≥0∵cosx≥0⇒x∉π,2πIf x∈(0,π2],   then cosx≤sinx⇒cosx≤sinx ⇒x∈π4,π2 If x∈π2,π,  then cosx≤sinx⇒-cosx≤sinx ∵cosx is negative ⇒tanx≤-1 ⇒x∈π2,3π4 ∴x∈π4,3π4
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