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Questions  

If 0x2π and cosxsinx, then

a
x∈0,π4
b
x∈π4,2π
c
π4,3π4
d
0,π

detailed solution

Correct option is C

We have cosx≤sinx⇒sinx≥0∵cosx≥0⇒x∉π,2πIf x∈(0,π2],   then cosx≤sinx⇒cosx≤sinx ⇒x∈π4,π2 If x∈π2,π,  then cosx≤sinx⇒-cosx≤sinx ∵cosx is negative ⇒tanx≤-1 ⇒x∈π2,3π4 ∴x∈π4,3π4

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