a→=i^+2j^+3k^,b→=2i^−j^+k^ and c→=3i^+j^+4k^ vectors are so placed that the end point of one vector is the starting point of the next vector. Then the vectors are
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a
not coplanar
b
coplanar but cannot form a triangle
c
coplanar and form a triangle
d
coplanar and can form a right-angled triangle
answer is B.
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Detailed Solution
Note that a→+b→=i^+2j^+3k^+2i^−j^+k^=3i^+j^+4k^=c→