$$I=$$∫$$sec2xcosec2xdx$$

Correct option is 1Tanx−cotx+c

Questions

$I = \int \sec^{2} x \cos e c^{2} x d x$

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Tanx−cotx+c

Tanx+cotx+c

Cotx−cosecx+c

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detailed solution

Correct option is A

=∫cos2⁡x+sin2⁡xcos2⁡xsin2⁡xdx=∫sec2⁡x+cos⁡ec2xdx=tan⁡x−cot⁡x+c

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I=∫sec2xcosec2xdx

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$I = \int \sec^{2} x \cos e c^{2} x d x$