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$I_{1} = \int_{0}^{4} [x - \frac{1}{2}] d x and I_{2} = \int_{0}^{π} \sqrt{\frac{1 + \cos 2 x}{2}} d x then ([.] denotes the G.I.F.)$

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I1=6I2

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Correct option is B

I1=4, I2=2⇒I1=2I2

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I1=∫04x-12dx and I2=∫0π1+cos2x2dx then ([.] denotes the G.I.F.)

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$I_{1} = \int_{0}^{4} [x - \frac{1}{2}] d x and I_{2} = \int_{0}^{π} \sqrt{\frac{1 + \cos 2 x}{2}} d x then ([.] denotes the G.I.F.)$