$$I=$$∫$$x2+x+1dx$$ is equal to

Correct option is 3x+122x2+x+1+38logx+12+x2+x+1+C

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$I = \int \sqrt{x^{2} + x + 1} d x is equal to$

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x+122x2+x+1−34logx+12+x2+x+1+C

x+122x2+x+1+34logx+12+x2+x+1+C

x+122x2+x+1+38logx+12+x2+x+1+C

x+122x2+x+1−38logx+12+x2+x+1+C

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detailed solution

Correct option is C

I=∫x2+x+1dx=∫x+122−14+1dx=∫x+122+322dx Use :∫x2+a2=x2x2+a2+a22log⁡x+x2+a2I=x+122x2+x+1+38logx+12x2+x+1+C

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I=∫x2+x+1dx is equal to

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$I = \int \sqrt{x^{2} + x + 1} d x is equal to$