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I=x21x32x42x2+1dx equal to

 

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a
2x4−2x2+1+C
b
2x4−2x2+1x3+C
c
2x4−2x2+1x+C
d
2x4−2x2+12x2+C

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detailed solution

Correct option is D

I=∫1/x3−1/x52−2/x2+1/x4dxput 2−2x2+1x4=t2⇒4x3+4x5dx=2tdt∴   I=12∫tdtt=12t+C=122−2x2+1x4+C=2x4−2x2+12x2+C


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