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If $A = [\begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & 1 \\ 0 & â 2 & 4 \end{array}], 6 A^{â 1} = A^{2} + c A + d I$ then (c,d) is

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(â 6, 11)

(â11, 6)

(11, 6)

(6, 11)

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Correct option is A

6Aâ1=A2+cA+dIâ 6I=A3+cA2+dAWe have A2=1000110â241000110â24=1000â150â1014and A3=A2A=1000â150â10141000110â24=1000â11190â3846Now, 6I=A3+cA2+dA6=1+c+d, 0=19+5c+d6=â11âc+d6=46+14c+4d, 0=â38â10câ2dâ d=11, c=â6

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If A=1000110â24,6Aâ1=A2+cA+dI then (c,d) is

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If $A = [\begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & 1 \\ 0 & â 2 & 4 \end{array}], 6 A^{â 1} = A^{2} + c A + d I$ then (c,d) is