First slide
Applications of determinant
Question

If a2+λ2ab+caabb2+λ2bc+ca+bcc2+λ2λcbcλabaλ=1+a2+b2+c23, then the value of λ is

Moderate
Solution

We observe that the elements in the pre-factor are the cofactors of the corresponding elements of the post-factor. Hence,

λcbcλabaλ3=λλ2+a2+b2+c23=1+a2+b2+c23

 λ=1

Alternate solution:

Writing a = 0, b = 0, c = 0on both sides, we get

λ6λ3=1 or λ=1

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