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$If \bar{AB} = \bar{i} + 2 \bar{j} - \bar{k}, \bar{BC} = 2 \bar{i} + \bar{j} + k represent two adjacent sides of Δ ABC, then$ $\frac{\sin A - \cos B}{\tan C} =$

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Correct option is D

cos(AB¯,BC¯)=2+2−166⇒cos(π−B)=12B=120° Also AB=BC⇒A=C=30°sin30−cos120tan30=3

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If AB¯=i¯+2j¯-k¯,BC¯=2i¯+j¯+k represent two adjacent sides of ΔABC , then sinA-cosBtanC=

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$If \bar{AB} = \bar{i} + 2 \bar{j} - \bar{k}, \bar{BC} = 2 \bar{i} + \bar{j} + k represent two adjacent sides of Δ ABC, then$ $\frac{\sin A - \cos B}{\tan C} =$