If AB=0, then for the matrices A=cos2θcosθsinθcosθsinθsin2θ and B=cos2ϕcosϕsinϕcosϕsinϕsin2ϕ θ-ϕ is
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a
an odd multiple of π2
b
an odd multiple of π
c
an even multiple of π2
d
0
answer is A.
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Detailed Solution
We have AB=cos2θcosθsinθcosθsinθsin2θcos2ϕcosϕsinϕcosϕsinϕsin2ϕ =cos2θcos2ϕ+cosθsinθcosϕsinϕcos2θcosϕsinϕ+cosθsinθsin2ϕcosθsinθcos2ϕ+sin2θcosϕsinϕcosθsinθcosϕsinϕ+sin2θsin2ϕ =cos(θ−ϕ)cosθcosϕcosθsinϕsinθcosϕsinθsinϕ Since AB=0,∴cos(θ−ϕ)=0∴(θ−ϕ) is an odd multiple of π2