Q.

If the absolute value of the difference of roots of the  equation x2+px+1=0 exceeds 3p then

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a

−1

b

0≤p<4

c

p<−1 or p>4

d

p>4

answer is D.

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Detailed Solution

|α−β|>3p⇒ (α+β)2−4αβ>3p⇒ p2−3p−4>0 and p>0⇒ (p−4)(p+1)>0 and p>0⇒ p>4
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If the absolute value of the difference of roots of the  equation x2+px+1=0 exceeds 3p then