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Questions  

If the absolute value of the difference of the roots of the equation x2+ax+1=0 exceeds 3a, then

a
a∈(−∞,−1)∪(4,∞)
b
a∈(4,∞)
c
a∈(−1,4)
d
a∈[0,4)

detailed solution

Correct option is A

We have, |α−β|>3a⇒|α−β|2>3a⇒(α+β)2−4αβ>3a⇒a2−4>3a⇒a2−3a−4>0⇒(a−4)(a+1)>0⇒a∈(−∞,−1)∪(4,∞)

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