If AD, BE and CF are the altitudes of ∆ABC whose vertex A is the point (-4, 5). Also, the coordinates of the points E and F are (4,1) and (-1, -4) respectively. Then, equation of BC is

Slope of AB=5−(−4)−4+1=−3∴  Equation of AB≡3x+y+7=0--------(i) Slope of CF=13∴  Equation of CF:x−3y−11=0----(ii) Slope of AC=5−1−4−4=−12∴  Equation of AC:x+2y−6=0----(iii)Slope of BE - 2 ∴  Equation of BE:2x−y−7=0---(iv) Solving (i) and (iv), we get B≡(0,−7) Solving (ii) and (iii), we get C≡(8,−1) Slope of BC=−7+10−8=34∴  Equation of BC:3x−4y−28=0