If all the lines given by the equation (3sinθ+5cosθ)x+(7sinθ−3cosθ)y+11(sinθ−cosθ)=0 pass through a fixedpoint P for all θ∈R, then the distance of P from Q(7 ,- 10) is
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answer is 10.
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Detailed Solution
We have equation of family of straight lines as (3x+7y+11)sinθ+(5x−3y−11)cosθ=0Lines are concurrent at point of intersection of lines 3x+7y+11=0 and 5x−3y−11=0Point of intersection is P(1,-2).Distance of point P from point Q (7,- 10) is 62+82=10