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If 8 AMS are intersected between 2 and 3    3rd AM

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a
5/3
b
2/3
c
7/3
d
1/3

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detailed solution

Correct option is C

2,a1,a2,a3…….a8,3 are in A.P 3=t10=a+9d=2+9d d=19a3=t4=2+3d=2+13=73


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