First slide

Means - A.M/G.M/H.M

Question

If 8 AMS are intersected between 2 and 3 3^rd AM

Moderate

A

$5 / 3$
B

$2 / 3$
C

$7 / 3$
D

$1 / 3$

Solution

$\begin{array}{l} 2, a_{1}, a_{2}, a_{3} \dots \dots . a_{8}, 3 are in A.P \\ 3 = t_{10} = a + 9 d = 2 + 9 d d = \frac{1}{9} \end{array}$
$a_{3} = t_{4} = 2 + 3 d = 2 + \frac{1}{3} = \frac{7}{3}$

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