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If the angle between the lines $3 y - x + 4 = 0$ and $x + y - 6 = 0$ is q, then tan q is equal to.

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3+1

3-1

2+3

3+2

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detailed solution

Correct option is C

Slopes of the given lines are 13 and -1, so tanθ=13+11-13=3+13-1=2+3

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If the angle between the lines 3 y – x + 4 = 0 and x + y – 6 = 0 is q, then tan q is equal to.

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Ready to Test Your Skills?

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If the angle between the lines $3 y - x + 4 = 0$ and $x + y - 6 = 0$ is q, then tan q is equal to.