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If the angles $A, B, C$ of a triangle are in $A . P .$ such that $\sin (2 A + B) = 1 / 2$ then $\sin (B + 2 C) =$

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Correct option is A

B=60∘,sin⁡(2A+B)=1/2⇒2A+B=150∘⇒A=45∘,C=75∘so that B+2C=210∘=180∘+30∘⇒sin⁡(B+2C)=−sin⁡30∘=−1/2

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If the angles A, B, C of a triangle are in A.P. such that sin⁡(2A+B)=1/2 then sin⁡(B+2C)=

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Ready to Test Your Skills?

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If the angles $A, B, C$ of a triangle are in $A . P .$ such that $\sin (2 A + B) = 1 / 2$ then $\sin (B + 2 C) =$