If the angles A, B, C of a triangle are in A.P. such that sin(2A+B)=1/2 then sin(B+2C)=
-12
12
32
B=60∘,sin(2A+B)=1/2⇒2A+B=150∘
⇒A=45∘,C=75∘
so that B+2C=210∘=180∘+30∘
⇒sin(B+2C)=−sin30∘=−1/2