Q.
If the angles A < B < C of a triangle are in A.P ., then
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a
c2=a2+b2−ab
b
b2=a2+c2−ac
c
c2=a2+b2
d
None f these
answer is B.
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Detailed Solution
A+C=2B and A+B+C=1800 so,B=600 ∴cos600=a2+c2−b22ac⇒b2=a2+c2−ac
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