Q.

If  the angles A < B < C of a triangle are in A.P ., then

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a

c2=a2+b2−ab

b

b2=a2+c2−ac

c

c2=a2+b2

d

None f these

answer is B.

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Detailed Solution

A+C=2B  and  A+B+C=1800 so,B=600 ∴cos600=a2+c2−b22ac⇒b2=a2+c2−ac
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If  the angles A < B < C of a triangle are in A.P ., then