If the angles made by the normal of the plane $$2x+3y$$−$$4z$$−$$16=0$$ with the coordinates axes X, Y, Z are , then Cos−$$1k1$$,Cos−$$1k2$$,Cos−$$1k3$$ respectively are

Question

If the angles made by the normal of the plane $$2x+3y$$−$$4z$$−$$16=0$$ with the coordinates axes X, Y, Z are , then Cos−$$1k1$$,Cos−$$1k2$$,Cos−$$1k3$$ respectively are

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The d.r’s of normal of the plane $$2x+3y$$−$$4z$$−$$16=0$$ are $$2$$,$$3$$,−$$4$$ and the d.c’s are  $$229$$,$$329$$,−$$429$$∴$$cos$$α$$=229$$,$$cos$$β$$=329$$,$$cos$$γ$$=$$−$$429Where$$ α,β,γ are the angle made by the normal with X, Y, Z axes respectiely.∴α$$=Cos$$−$$1229$$,β$$=Cos$$−$$1329$$γ$$=Cos$$−$$1$$−$$429$$ ∴$$k1$$,$$k2$$,$$k3$$ values are  $$229$$,$$329$$,−$$429$$ respectively

If the angles made by the normal of the plane $2 x + 3 y - 4 z - 16 = 0$ with the coordinates axes X, Y, Z are , then $C o s^{- 1} k_{1}, C o s^{- 1} k_{2}, C o s^{- 1} k_{3}$ respectively are

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If the angles made by the normal of the plane 2x+3y−4z−16=0 with the coordinates axes X, Y, Z are , then Cos−1k1,Cos−1k2,Cos−1k3 respectively are

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If the angles made by the normal of the plane $2 x + 3 y - 4 z - 16 = 0$ with the coordinates axes X, Y, Z are , then $C o s^{- 1} k_{1}, C o s^{- 1} k_{2}, C o s^{- 1} k_{3}$ respectively are