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Questions  

If the antiderivative of f(x) =

sinxsin2x+4cos2x is (1/3)tan1((1/3)g(x))+C then

g(x) is equal to

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a
sec⁡x
b
tan x
c
sin x
d
cos x

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detailed solution

Correct option is A

f(x)=sin⁡xsin2⁡x+4cos2⁡x=tan⁡xsec⁡xtan2⁡x+4=tan⁡xsec⁡xsec2⁡x+3Putting sec⁡x=t,dxsec⁡xtan⁡x=dt so∫f(x)dx=∫dtt2+3=13tan−1⁡sec⁡x3+C


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