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 If an anti-derivative of f(x) is ex and that of g(x) is cos x, then f(x)cos xdx+g(x)exdx is equal to 

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a
f(x)⋅g(x)+C
b
f(x)+g(x)+C
c
excos ⁡x+C
d
f(x)−g(x)+1

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detailed solution

Correct option is C

∫f(x)cos ⁡xdx+∫g(x)exdx=ex2(cos ⁡x+sin⁡ x)−ex2(sin⁡ x−cos⁡ x)+C=ex2(2cos ⁡x)+C=excos ⁡x+C


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