If an anti-derivative of f(x) is ex and that of g(x) is cos x, then ∫f(x)cos xdx+∫g(x)exdx is equal to
f(x)⋅g(x)+C
f(x)+g(x)+C
excos x+C
f(x)−g(x)+1
∫f(x)cos xdx+∫g(x)exdx
=ex2(cos x+sin x)−ex2(sin x−cos x)+C=ex2(2cos x)+C=excos x+C