If α is any of 7th roots of unity, then α= cis 2Kπ7(K=0 to 6) and ∑i=16 αi=−1(α≠1) and α7=1. Then answer the following The equation whose roots are α+α2+α4 and α3+α5+α6 is (α≠1) If f(x)=1+2x+3x2+4x3+5x4+6x5+7x6 then for α≠1, f(x)+f(αx)+fα2x+fα3x+−−−+fα6x=
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