If α and β,α and γ,α and δ are the roots of the equations ax2+2bx+c=0,2bx2+cx+a=0 and cx2+ax+2b=0 respectively, where e, b, and c are positive real numbers, then α+α2=
abc
a + 2b + c
-1
0
Since α is root of all equations
aα2+2bα+c=02bα2+cα+a=0cα2+aα+2b=0
Adding we get (a+2b+c)α2+α+1=0
a+2b+c≠0 as a,b,c>0⇒α2+α+1=0 or α2+α=−1