If α and β, α and γ, α and δ are the roots of the equations ax2+2bx+c=0, 2bx2+cx+a=0 and cx2+ax+2b=0 respectively, where a, b and c are positive real numbers, then α+α2=
-1
0
abc
a+2b+c
Here α+β=-2ba
γ+α=-c2b, α+δ=-ac
and αβ=ca, αγ=a2b, αδ=2bc
⇒α+δ=-1αβ, α2β+αβδ=-1 ...(i)
⇒α+β=-1αγ, α2γ+αβγ=-1 ...(ii)
⇒α+γ=-1αδ,α2δ+αβγ=-1 ...(iii)
Solve equations (i), (ii) and (iii), we get α=-1