If Δ1,Δ2 are the areas of incircle and circumcircle of a triangle with sides 3,4 and 5 then Δ1Δ2=

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answer is 0.16.

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Detailed Solution

a=3,b=4,c=5 are sides of right angle triangler=Δs=12aba+b+c2=3(4)3+4+5=1R=hypotenuse2=52∴Δ1Δ2=πr2πR2=(1)2522=425

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