Questions
If are in arithmetic progression and then is equal to
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a
909
b
75
c
750
d
900
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Correct option is D
Given that, a1+a5+a10+a15+a20+a24=225⇒ a1+a24+a5+a20+a10+a15=225⇒ 3a1+a24=225⇒ a1+a24=75[∵in an AP the sum of the terms equidistant from the beginning and the end is same and is equal to the sum of the first and last term] ∴ a1+a2+…+a24=n2(a+l)=242a1+a24=12×75=900 [from eq.(i)]Similar Questions
If the sum of first terms of an is , then the sum of squares of these terms is
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