If (0, 1), (1, 1) and (1, 0) are the mid points of the sides of a triangle, the coordinates of its incentre are
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a
(2+2,2+2)
b
((2+2),−(2+2))
c
((2−2),(2−2))
d
((2−2),−(2−2))
answer is C.
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Detailed Solution
The given triangle is right-angled with verticesA(0, 0), B(2, 0) and C (0, 2).Coordinates of the incentre areax1+bx2+cx3a+b+c,ay1+by2+cy3a+b+c=22×0+2×2+2×022+2+2,22×0+2×0+2×222+2+2=(2−2,2−2)