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If α,β,γ are the real roots of the equation x33px2+3qx1=0 then the centroid of the triangle with vertices α,1α,β,1β and γ,1γ 

is at the point 

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a
(p, q)
b
(p/3, q/3)
c
(p + q.p - q)
d
(3p, 3q)

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detailed solution

Correct option is A

The centroid of the given triangle is the point α+β+γ3,1α+1β+1γ3=3p3,αβ+βγ+γα3αβγ=(p,q)[∵α+β+γ=3p,αβ+βγ+γα=3q,αβγ=1]

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