If α, β are the roots of ax2+bx+c=0 and α+β, α2+β2, α3+β3 are in G.P., when ∆=b2-4ac, then
∆≠0
b∆=0
cb≠0
c∆=0
(α2+β2)2=(α+β)(α3+β3)
(b2-2aca2)2=(-ba)(-b2+3abca3)
⇒4a2c2=acb2⇒ac(b2-4ac) As a≠0⇒c∆=0