If α and β are the roots of cx2+bx+a=0, then the roots of equation a(x+1)2+b(x+1)+c=0 are
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a
α−1,β−1
b
α+1α,1+ββ
c
α+1,β+1
d
1−αα,1−ββ
answer is D.
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Detailed Solution
Roots of the equation cx2+bx+a=0 are α and β . So, roots of the equation ax2+bx+c=0 are 1α,1β . Hence, roots of the equation a(x+1)2+b(x+1)+c=0 are: 1α−1=1−αα and 1β−1=1−ββ