If α and β are the roots of cx2+bx+a=0, then the roots of equation a(x+1)2+b(x+1)+c=0 are
α−1,β−1
α+1α,1+ββ
α+1,β+1
1−αα,1−ββ
Roots of the equation cx2+bx+a=0 are α and β .
So, roots of the equation ax2+bx+c=0 are 1α,1β .
Hence, roots of the equation a(x+1)2+b(x+1)+c=0 are:
1α−1=1−αα and 1β−1=1−ββ