First slide
Theory of equations
Question

If α,β,γ,σ are the roots of the equation x4+4x36x2+7x9=0 then the value of 1+α21+β21+γ21+σ2 is

Moderate
Solution

Since α,β,γ,σ are the roots of the given equation  x4+4x36x2+7x9=(xα)(xβ)(xγ)(xσ)

Putting x = i and then x == -i, we get

and 14i+6+7i9=(iα)(iβ)(iγ)(iσ)1+4i+67i9=(iα)(iβ)(iγ)(iσ)

Multiplying these two, we get

(2+3i)(23i)=1+α21+β21+γ21+σ2 13=1+α21+β21+γ21+σ2

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