If α, β are the roots of the equation ax2+bx+c=0 then the equation whose roots are α+1β and β+1α, is

Here α+β=-ba and αβ=caIf roots are α+1β,β+1α, then sum of roots are=(α+1β)+(β+1α)=(α+β)+α+βαβ=- bac(a+c)and product =(α+1β)(β+1α) =αβ+1+1+1αβ=2+ca+ac =2ac+c2+a2ac=(a+c)2acHence required equation is given byx2+bac(a+c)x+(a+c)2ac=0⇒acx2+(a+c)bx+(a+c)2=0