If α, β are the roots of the equation x2−2x+3=0. Then the equation whose roots are P=α3−3α2+5α−2 and Q=β3−β2+β+5 is
x2+3x+2=0
x2-3x-2=0
x2-3x+2=0
none of these
Given, α, β are roots of equation
x2−2x+3=0
⇒ α2−2α+3=0 (1) and β2−2β+3=0 (2)
⇒ α2=2α−3 or α3=2α2−3α⇒ P =2α2−3α−3α2+5α−2 =−α2+2α−2=3−2=1 [Using (1)]
Similarly, we have Q = 2.Now, sum of roots is 3 and product of roots is 2. Hence, therequired equation is x2−3x+2=0