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Questions  

If α and β are the roots of the equation x2x+1=0, then α2009+β2009=

a
2
b
−2
c
−1
d
1

detailed solution

Correct option is D

x2−x+1=0         ⇒x=1+1−42 x=1+3i2 α=12+i32.      β=12−i32 α=cosπ3+isinπ3,β=cosπ3−isinπ3 α2009+β2009=2cos2009(π3) =2cos[668π+π+2π3]=2cos(π+2π3) =−2cos2π3=−2(−12)=1

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