If α , β are roots of the equation ax2+bx+c=0 then the equation whose roots are 2α+3β and 3α+2β is
ab x2−(a+b)cx+(a+b)2=0
ac x2−(a+c)bx+(a+c)2=0
ac x2+(a+c)bx−(a+c)bx−(a+c)2=0
none of these
We have,
α+β=−ba,αβ=ca
The required equation is
x2−5x(α+β)+(2a+3β)(3α+2β)=0⇒x2+5xba+6α2+β2+13αβ=0⇒x2+5bxa+6(α+β)2+αβ=0⇒x2+5bax+6b2a2+ca=0⇒a2x2+5abx+6b2+ac=0