If α,β are the roots of the equation ax2+bx+c=0, then the value of α3+β3 is
3abc+b3a3
a3+b33abc
3abc−b3a3
−3abc+b3a3
We have
α+β=−ba,αβ=ca
Now, α3+β3=(α+β)3−3αβ(α+β)
=−ba3−3ca−ba=3abc−b3a3