First slide
Theory of equations
Question

If α, β are the roots of the equation x2-(1+n2)x+12(1+n2+n4)=0 then the value of α2+β2 is

Moderate
Solution

α+β=1+n2; αβ=12(1+n2+n4)

α2+β2=(α+β)2-2αβ

=(1+n2)2-2.12(1+n2+n4)

=1+n4+2n2-1-n2-n4α2+β2=n2.

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