If α, β are the roots of the equation x2-(1+n2)x+12(1+n2+n4)=0 then the value of α2+β2 is
2n
n3
n2
2n2
α+β=1+n2; αβ=12(1+n2+n4)
∴α2+β2=(α+β)2-2αβ
=(1+n2)2-2.12(1+n2+n4)
=1+n4+2n2-1-n2-n4⇒α2+β2=n2.