If α,β are the roots of the equation x2+px−r=0 and α3,3β are the roots of the equation x2+qx−r=0 , then r eqaul

Roots of the equation x2+px−r=0 are α,β∴ α+β=−p-----(1) and  αβ=-r----(2) Also, roots of the equation x2+qx−r=0 are α3 and 3β∴ α3+3β=−q⇒ α+9β=−3q------(3) And α3(3β)=−r  or  αβ=−rOn solving, (1) and (3), we getα=3(q−3p)8, β=p−3q8 Now αβ=−r=3(q-3p)(p−3q)64