If α,β are roots of the equation  2x2+6x+b=0(b<0), then αβ+βα is less than

We have, α+β=-3 and aβ=b2Since b < 0, therefore discriminant D := 36 - 4b > 0. So  α and β are real.Now, αβ+βα=α2+β2αβ=(α+β)2−2αβαβ=(α+β)2αβ−2=18b−2⇒ αβ+βα<−2                ∵b<0