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If $α, β$ are roots of the equation $x^{2} + 2 x + 4 = 0$ , then $\frac{1}{α^{3}} + \frac{1}{β^{3}}$ is equal to

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Correct option is D

Here, α+β=-2 and αβ=4∴1α3+1β3=α3+β3(αβ)3=(α+β)3-3αβ(α+β)(αβ)3=(-2)3-3(-2)(4)(4)3=1664=14

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If α, β are roots of the equation x2+2x+4=0, then 1α3+1β3 is equal to

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If $α, β$ are roots of the equation $x^{2} + 2 x + 4 = 0$ , then $\frac{1}{α^{3}} + \frac{1}{β^{3}}$ is equal to