First slide
Theory of equations
Question

If α and β are the roots of the equation x2-a(x+1)-b=0 then (α+1)(β+1)=

Moderate
Solution

Given equation x2-a(x+1)-b=0

x2-ax-a-b=0α+β=a, αβ=-(a+b)

Now (α+1)(β+1)=αβ+α+β+1

=-(a+b)+a+1=1-b

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