If α and β are the roots of the equation, 7x2-3x-2=0, then the value of α1−α2+β1−β2 is equal to:

Given α and β are the roots of the equation, 7x2-3x-2=0 , hence α+β=37,αβ=-27Consider α2+β2=α+β2-2αβ=949+47==3749 And the required expression is α1−α2+β1−β2=α+β−αβα+β1−α2+β2+αβ2=37+6491−3749+449=2716