If 1, 2, 3 and 4 are the roots of the equation x4+ax3+bx2+cx+d=0 , then a+2b+c=

The given equation is x4+ax3+bx2+cx+d=0 The given roots are α=1,β=2,γ=3,δ=4⇒a=α+β+γ+δ=−10⇒b=(α+β)(γ+δ)+αβ+γδ=35⇒c=(α+β)γδ+(γ+δ)αβ=-50∴ a+2b+c=−10+2(35)-50=10