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Q.

If  α,  β,  γ are the roots of x3−3x+1=0  then the equation whose roots are α−1βγ , β−1γα  , γ−1αβ   is

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a

x3−3x+8=0

b

x3−6x+8=0

c

x3−9x+8=0

d

x3−12x+8=0

answer is D.

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Detailed Solution

α+β+γ = 0 , αβ+βγ+γ =-3      αβγ=-1now y=αβγ-1βγ=−2βγ=−2α−1=2α α=y2f(y2)=0⇒y3−12y+8=0
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