If α,β are the roots of ax2+ bx+ c =0 then the equation whose roots α+1β , β+1α is
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a
cx2+bx+a=0
b
acx2+b(a+c)x+(a+c)2=0
c
cx2−bx+a=0
d
acx2−b(a+c)x+(a+c)2=0
answer is B.
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Detailed Solution
The given equation is ax2+ bx+ c =0 Given roots of equation are α,β Then sum of the roots α+β=−ba Product of the roots αβ=ca If the roots are α+1β , β+1α , thenSum of the roots=α+1β+β+1α=α+β+α+βαβ =−ba−bc (∵α+β=−ba, αβ=ca) =−b(a+c)ac Product of the roots = αβ+1+1+1αβ =(c+a)2ac General quadratic equation is x2−(a+b)x+ab=0 (a,b are roots )Required equation is x2−(−b(a+c)ac)x+(c+a)2ac=0 ⇒ acx2+b(a+c)x+(c+a)2=0