Questions
If are the roots of and if then
a
Vn+1=aVn+bVn-1
b
Vn+1=aVn+aVn-1
c
Vn+1=aVn-bVn-1
d
Vn+1=aVn-1-bVn
detailed solution
Correct option is C
Multiplying x2-ax+b=0 by xn-1xn+1-axn+bxn-1=0 ...(i)α,β are roots of x2-ax+b=0, therefore they will satisfy (i) also αn+1-aαn+bαn-1=0 ...(ii)and βn+1-αβn+bβn-1=0 ...(iii)adding (ii) and (iii)(αn+1+βn+1)-a(αn+βn)+b(αn-1+βn-1)=0or Vn+1=aVn-bVn-1(Given αn+βn=Vn)Talk to our academic expert!
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