If α,β are the roots of x2-ax+b=0 and if αn+βn=Vn, then
Vn+1=aVn+bVn-1
Vn+1=aVn+aVn-1
Vn+1=aVn-bVn-1
Vn+1=aVn-1-bVn
Multiplying x2-ax+b=0 by xn-1
xn+1-axn+bxn-1=0 ...(i)
α,β are roots of x2-ax+b=0, therefore they will satisfy (i) also αn+1-aαn+bαn-1=0 ...(ii)
and βn+1-αβn+bβn-1=0 ...(iii)
adding (ii) and (iii)
(αn+1+βn+1)-a(αn+βn)+b(αn-1+βn-1)=0
or Vn+1=aVn-bVn-1(Given αn+βn=Vn)