First slide
Theory of expressions
Question

If α,β are the roots of x2-ax+b=0 and if αn+βn=Vn, then

Moderate
Solution

Multiplying x2-ax+b=0 by xn-1

xn+1-axn+bxn-1=0    ...(i)

α,β are roots of x2-ax+b=0, therefore they will satisfy (i) also αn+1-n+n-1=0    ...(ii)

and βn+1-αβn+n-1=0     ...(iii)

adding (ii) and (iii)

(αn+1+βn+1)-a(αn+βn)+b(αn-1+βn-1)=0

or Vn+1=aVn-bVn-1(Given αn+βn=Vn)

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