if α, β are the roots of ax2+bx+c=0;α+h, β+h are the roots of px2+qx+r=0; and D1,D2the respective discriminants of these equations, then D1:D2=
a2p2
b2q2
c2r2
none of these
Let A=α+h and B=β+h. Then,
A−B=(α+h)−(β+h)=α−β⇒(A−B)2=(α−β)2⇒ (A+B)2−4AB=(α+β)2−4αβ⇒ b2a2−4ca=q2p2−4rp⇒ b2−4aca2=42−4rp2⇒D1a2=D2p2⇒D1D2=a2p2