First slide
Theory of equations
Question

if α, β are the roots of ax2+bx+c=0;α+h, β+h are the roots of px2+qx+r=0; and D1,D2the respective discriminants of these equations, then D1:D2=

Moderate
Solution

Let A=α+h and B=β+h. Then,

AB=(α+h)(β+h)=αβ(AB)2=(αβ)2 (A+B)24AB=(α+β)24αβ b2a24ca=q2p24rp b24aca2=424rp2D1a2=D2p2D1D2=a2p2

 

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